-5n^2+10n+15=0

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Solution for -5n^2+10n+15=0 equation:



-5n^2+10n+15=0
a = -5; b = 10; c = +15;
Δ = b2-4ac
Δ = 102-4·(-5)·15
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{400}=20$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-20}{2*-5}=\frac{-30}{-10} =+3 $
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+20}{2*-5}=\frac{10}{-10} =-1 $

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